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2004 AMC 12B Problems/Problem 17

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Problem

For some real numbers a and b, the equation 8x^3 + 4ax^2 + 2bx + a = 0 has three distinct positive roots. If the sum of the base-2 logarithms of the roots is 5, what is the value of a?

\mathrm{(A)}\ -256\qquad\mathrm{(B)}\ -64 \qquad\mathrm{(C)}\ -8\qquad\mathrm{(D)}\ 64 \qquad\mathrm{(E)}\ 256

Solution

Let the three roots be x_1,x_2,x_3. \log_2 x_1 + \log_2 x_2 + \log_2 x_3 = \log_2 x_1x_2x_3= 5 \Longrightarrow x_1x_2x_3 = 32 By Vieta’s formulas, 8(x-x_1)(x-x_2)(x-x_3) = 8x^3 + 4ax^2 + 2bx + a gives us that a = -8x_1x_2x_3 = -256 \Rightarrow \mathrm{(A)}.

See also

2004 AMC 12B (ProblemsResources)
Preceded by
Problem 16
Followed by
Problem 18
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