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2004 AMC 12B Problems/Problem 9

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Problem

The point (-3,2) is rotated 90^\circ clockwise around the origin to point B. Point B is then reflected over the line x=y to point C. What are the coordinates of C?

\mathrm{(A)}\ (-3,-2)\qquad\mathrm{(B)}\ (-2,-3)\qquad\mathrm{(C)}\ (2,-3)\qquad\mathrm{(D)}\ (2,3)\qquad\mathrm{(E)}\ (3,2)

Solution

The entire situation is in the picture below. The correct answer is \boxed{\mathrm{(E)}\ (3,2)}.

unitsize(1cm);defaultpen(0.8);pair A=(-3,2), B=rotate(-90)*A, C=(3,2);dot(A); dot(B); dot(C);draw( A -- (0,0) -- B -- C, Dott...

See Also

2004 AMC 12B (ProblemsResources)
Preceded by
Problem 8
Followed by
Problem 10
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
Want to learn how to tackle those tough MATHCOUNTS and AMC counting and probability problems? Check out Art of Problem Solving's Introduction to Counting & Probability by David Patrick.
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