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2005 PMWC Problems/Problem I1

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Problem

What is the greatest possible number one can get by discarding 100 digits, in any order, from the number 123456789101112\ldots585960?

Solution

The length of the resulting number is the same no matter what, so to maximize the number we want to invoke the greedy algorithm - get as many 9s in the first several digits as possible. There are 9 + 2(51) = 111 digits in the original number, so after deleting 100 we will be left with 11 digits. There are six 9s in the string of numbers. Applying the greedy algorithm, we might expect to get 999999\ldots, but we promptly run out of digits. So instead, we start with 5 nines, 99999. We would then try to fit an 8 next, but again it turns out that we run out of digits. So we continue with 7. We still need five more digits, and we have six left to choose from. It quickly becomes apparent that our answer is 99999785960.

See also

2005 PMWC (Problems)
Preceded by
First question
Followed by
Problem I2
I: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
T: 1 2 3 4 5 6 7 8 9 10
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