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2005 PMWC Problems/Problem T2

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Problem

Compute the sum of a, b, and c given that \dfrac{a}{2}=\dfrac{b}{3}=\dfrac{c}{5} and the product of a, b, and c is 1920.

Solution

\dfrac{abc}{2*3*5}=64=\dfrac{a^3}{8}=\dfrac{b^3}{27}=\dfrac{c^3}{125}


a=8


b=12


c=20


a+b+c=\boxed{40}

See also

2005 PMWC (Problems)
Preceded by
Problem T1
Followed by
Problem T3
I: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
T: 1 2 3 4 5 6 7 8 9 10
Looking for a challenging algebra text? Preparing for MATHCOUNTS or the AMC exams?
Check out Art of Problem Solving's Introduction to Algebra by Richard Rusczyk.
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