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2005 PMWC Problems/Problem T7

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Problem

Skipper’s doghouse has a regular hexagonal base that measures one metre on each side. Skipper is tethered to a 2-metre rope which is fixed to a vertex. What is the area of the region outside the doghouse that Skipper can reach? Calculate an approximate answer by using \pi=3.14 or \pi=22/7.

Solution

Sorry, the GeoGebra Applet could not be started. Please make sure that Java 1.4.2 (or later) is installed and activated. (click here to install Java now)

The big sector has a radius of 2 and is 2/3 of the total circle that it used to be a part of, and thus has an area of 4\pi*\frac{2}{3}=\frac{8}{3}\pi. The two little sectors each have radius 1 and are 1/6 the total area of their circle, so the area of each of those is \frac{\pi}{6}. Adding, we get \frac{8}{3}\pi+\frac{\pi}{6}+\frac{\pi}{6}=3\pi. Then approximate.

See also

2005 PMWC (Problems)
Preceded by
Problem T6
Followed by
Problem T8
I: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
T: 1 2 3 4 5 6 7 8 9 10
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