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2006 AMC 10B Problems/Problem 13

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Problem

Joe and JoAnn each bought 12 ounces of coffee in a 16 ounce cup. Joe drank 2 ounces of his coffee and then added 2 ounces of cream. JoAnn added 2 ounces of cream, stirred the coffee well, and then drank 2 ounces. What is the resulting ratio of the ammount of cream in Joe's coffee to that in JoAnn's coffee?

\mathrm{(A) \ } \frac{6}{7}\qquad \mathrm{(B) \ } \frac{13}{14}\qquad \mathrm{(C) \ }1 \qquad \mathrm{(D) \ } \frac{14}{13}\q...

Solution

After drinking and adding cream, Joe's cup has 2 ounces of cream.

After adding cream to her cup, JoAnn's cup had 14 ounces of liquid. By drinking 2 ounces out of the 14 ounces of liquid, she drank \frac{2}{14}=\frac{1}{7}th of the cream. So there is 2\cdot\frac{6}{7}=\frac{12}{7} ounces of cream left.

So the desired ratio is: \frac{2}{\frac{12}{7}} = \frac{7}{6} \Rightarrow E

See Also

Want to learn how to tackle those tough MATHCOUNTS and AMC counting and probability problems? Check out Art of Problem Solving's Introduction to Counting & Probability by David Patrick.
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