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2006 AMC 12B Problems/Problem 4

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Problem

Mary is about to pay for five items at the grocery store. The prices of the items are \ 7.99, \ 4.99, \ 2.99, \ 1.99, and \ 0.99. Mary will pay with a twenty-dollar bill. Which of the following is closest to the percentage of the \ 20.00 that she will receive in change?

\text {(A) } 5 \qquad \text {(B) } 10 \qquad \text {(C) } 15 \qquad \text {(D) } 20 \qquad \text {(E) } 25

Solution

The total price of the items is (8-.01)+(5-.01)+(3-.01)+(2-.01)+(1-.01)=19-.05=18.95

20-18.95=1.05

\frac{1.05}{20}=.0525 \Rightarrow \text{(A)}

See also

2006 AMC 12B (ProblemsResources)
Preceded by
Problem 3
Followed by
Problem 5
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
Looking for a challenging algebra text? Preparing for MATHCOUNTS or the AMC exams?
Check out Art of Problem Solving's Introduction to Algebra by Richard Rusczyk.
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