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2006 Canadian MO Problems/Problem 2

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Problem

Let ABC be an acute angled triangle. Inscribe a rectangle DEFG in this triangle so that D is on AB, E on AC, and F and G on BC. Describe the locus of the intersections of the diagonals of all possible rectangles DEFG.

Solution

The locus is the line segment which joins the midpoint of side BC to the midpoint of the altitude to side BC of the triangle.

Let r = \frac{AD}{AB} and let H be the foot of the altitude from A to BC. Then by similarity, \frac{AE}{AC} = \frac{GH}{BH} = \frac{FH}{CH} = r.

Now, we use vector geometry: intersection I of the diagonals of DEFG is also the midpoint of diagonal DF, so

I = \frac{1}{2}(D + F) = \frac{1}{2}((rA + (1 - r)B) + (rH + (1 - r)C)) = r \frac{A + H}{2} + (1 - r)\frac{B + C}{2},

and this point lies on the segment joining the midpoint \frac{A + H}{2} of segment AH and the midpoint \frac{B + C}{2} of segment BC, dividing this segment into the ratio r : 1 - r.

See also

2006 Canadian MO (Problems)
Preceded by
Problem 1
1 2 3 4 5 Followed by
Problem 3
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