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2006 Cyprus MO/Lyceum/Problem 13

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Problem

The sum of the digits of the number 10^{2006}-2006 is

\mathrm{(A)}\ 18006\qquad\mathrm{(B)}\ 20060\qquad\mathrm{(C)}\ 2006\qquad\mathrm{(D)}\ 18047\qquad\mathrm{(E)}\ \text{None o...

Solution

10^{2006} is a 1 followed by 2006 0's. When we subtract 2006, we will get something close to 2006 9's.

The last four digits are 10000 - 2006 = 7994, and so we have 2002 9s followed by 7994.

The sum of these is 2002 \cdot 9 + 7 + 9 + 9 + 4 = 18047 \Longrightarrow \mathrm{(D)}

See also

2006 Cyprus MO, Lyceum (Problems)
Preceded by
Problem 12
Followed by
Problem 14
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