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2007 AMC 10A Problems/Problem 17

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Problem

Suppose that m and n are positive integers such that 75m = n^{3}. What is the minimum possible value of m + n?

\text{(A)}\ 15 \qquad \text{(B)}\ 30 \qquad \text{(C)}\ 50 \qquad \text{(D)}\ 60 \qquad \text{(E)}\ 5700

Solution

3 \cdot 5^2m must be a perfect cube, so each power of a prime in the factorization for 3 \cdot 5^2m must be divisible by 3. Thus the minimum value of m is 3^2 \cdot 5 = 45, which makes n = \sqrt[3]{3^3 \cdot 5^3} = 15. These sum to 60\ \mathrm{(D)}.

See also

2007 AMC 10A (ProblemsResources)
Preceded by
Problem 16
Followed by
Problem 18
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