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2007 AMC 12A Problems/Problem 21

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Problem

The sum of the zeros, the product of the zeros, and the sum of the coefficients of the function \displaystyle f(x)=ax^{2}+bx+c are equal. Their common value must also be which of the following?

\textrm{(A)}\ \textrm{the\ coefficient\ of\ }x^{2}~~~ \textrm{(B)}\ \textrm{the\ coefficient\ of\ }x \textrm{(C)}\ \textrm{the\ y-intercept\ of\ the\ graph\ of\ }y=f(x) \textrm{(D)}\ \textrm{one\ of\ the\ x-intercepts\ of\ the\ graph\ of\ }y=f(x) \textrm{(E)}\ \textrm{the\ mean\ of\ the\ x-intercepts\ of\ the\ graph\ of\ }y=f(x)

Solution

By Vieta's formulas, the sum of the roots of a quadratic equation is \frac {-b}a, the product of the zeros is \frac ca, and the sum of the coefficients is a + b + c. Setting equal the first two tells us that \frac {-b}{a} = \frac ca \Rightarrow b = -c. Thus, a + b + c = a + b - b = a, so the common value is also equal to the coefficient of x^2 \Longrightarrow \textrm{A}.

To disprove the others, note that:

  • \mathrm{B}: then b = \frac {-b}a, which is not necessarily true.
  • \mathrm{C}: the y-intercept is c, so c = \frac ca, not necessarily true.
  • \mathrm{D}: an x-intercept of the graph is a root of the polynomial, but this excludes the other root.
  • \mathrm{E}: the mean of the x-intercepts will be the sum of the roots of the quadratic divided by 2.

See also

2007 AMC 12A (ProblemsResources)
Preceded by
Problem 20
Followed by
Problem 22
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