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2007 Cyprus MO/Lyceum/Problem 2

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Problem

Given the formula f(x) = 4^x, then f(x+1)-f(x) equals to

\mathrm{(A) \ } 4\qquad \mathrm{(B) \ } 4^x\qquad \mathrm{(C) \ } 2\cdot4^x\qquad \mathrm{(D) \ } 4^{x+1}\qquad \mathrm{(E) \...

Solution

f(x+1)-f(x)=4^{x+1}-4^x=4\cdot4^x-4^x=(4-1)\cdot4^x=3\cdot4^x\Longrightarrow\mathrm{ E}

See also

2007 Cyprus MO, Lyceum (Problems)
Preceded by
Problem 1
Followed by
Problem 3
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