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2007 Cyprus MO/Lyceum/Problem 21

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Problem

In the figure, three equal cycles of diameter 20\,\mathrm{ cm} represent pulleys, that are connected with a strap. If the distances between any two pulley center points are AB=3\,\mathrm{m}, AC=4\,\mathrm{m} and BC=5\,\mathrm{m}, then the length of the strap is

\mathrm{(A) \ } (12+20\pi)\,\mathrm{m}\qquad \mathrm{(B) \ } (12 + \pi)\,\mathrm{m}\qquad \mathrm{(C) \ } (12+ 4\pi)\,\mathrm...

Solution

The lengths of the straight parts of the strap are 3\,\mathrm{m}, 4\,\mathrm{m}, and 5\,\mathrm{m}. Their sum is 12\,\mathrm{m}. The curved parts of the band add up to a full circumference of one of the circles, so their sum is 20\pi\,\mathrm{m}. The total length of the strap is (12+20\pi)\,\mathrm{m}\Longrightarrow\mathrm{A}.

See also

2007 Cyprus MO, Lyceum (Problems)
Preceded by
Problem 20
Followed by
Problem 22
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