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2008 AMC 12A Problems/Problem 14

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Problem

What is the area of the region defined by the inequality |3x-18|+|2y+7|\le3?

\mathrm{(A)}\ 3\qquad\mathrm{(B)}\ \frac {7}{2}\qquad\mathrm{(C)}\ 4\qquad\mathrm{(D)}\ \frac{9}{2}\qquad\mathrm{(E)}\ 5

Solution

Area is invariant under translation, so after translating left 6 and up 3/2 units, we have the inequality

|3x| + |2y|\leq 3

which forms a diamond centered at the origin and vertices at (\pm 1, 0), (0, \pm 1.5). Thus the diagonals are of length 2 and 3. Using the formula A = \frac 12 d_1 d_2, the answer is \frac{1}{2}(2)(3) = 3 \Rightarrow \mathrm{(A)}.

See also

2008 AMC 12A (ProblemsResources)
Preceded by
Problem 13
Followed by
Problem 15
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
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