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2008 AMC 12B Problems/Problem 19

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Problem 19

A function f is defined by f(z) = (4 + i) z^2 + \alpha z + \gamma for all complex numbers z, where \alpha and \gamma are complex numbers and i^2 = - 1. Suppose that f(1) and f(i) are both real. What is the smallest possible value of | \alpha | + |\gamma |

\textbf{(A)} \; 1 \qquad \textbf{(B)} \; \sqrt {2} \qquad \textbf{(C)} \; 2 \qquad \textbf{(D)} \; 2 \sqrt {2} \qquad \textbf...

Solution

We need only concern ourselves with the imaginary portions of f(1) and f(i) (both of which must be 0). These are:

1) f(1) = i+\alpha_{imaginary}+\gamma_{imaginary}

2) f(i) = -i+i\alpha_{real}+\gamma_{imaginary}

Since \gamma_{imaginary} appears in both equations, we let it equal 0 to simplify the equations. This yields two single-variable equations. Equation 1 tells us that the imaginary part of \alpha must be -i, and equation 2 tells us that the real part of \alpha must be i/i = 1. Therefore, \alpha = 1-i. There are no restrictions on \gamma_{real}, so to minimize \gamma's absolute value, we let \gamma_{real} = 0.


| \alpha | + |\gamma | = |1-i| + |0| = \sqrt{2}, answer choice B.

See Also

2008 AMC 12B (ProblemsResources)
Preceded by
Problem 18
Followed by
Problem 20
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
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