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2008 Mock ARML 1 Problems/Problem 7

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Problem

Compute the number of 3-digit base-5 positive integer multiples of 7 that are also divisible by 7 when read in base 10 instead of base 5.

Solution

Let the number be \overline{abc}. Then 7 | 25a + 5b + c, 100a + 10b + c, and so it must divide their difference, so 7 | 75a + 5b \Longrightarrow 7|-2(a+b), from which it follows that 7|a+b. However, as a,b < 5, we have \{a,b\} = \{3,4\}, leading to \boxed{2} solutions: 343, 434.

See also

2008 Mock ARML 1 (Problems, Source)
Preceded by
Problem 6
Followed by
Problem 8
1 2 3 4 5 6 7 8
Want to learn how to tackle those tough AMC/AIME/Olympiad counting and probability problems? Check out Art of Problem Solving's Intermediate Counting & Probability by David Patrick.
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