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2009 AIME I Problems/Problem 9

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Problem

A game show offers a contestant three prizes A, B and C, each of which is worth a whole number of dollars from $1 to $9999 inclusive. The contestant wins the prizes by correctly guessing the price of each prize in the order A, B, C. As a hint, the digits of the three prices are given. On a particular day, the digits given were 1, 1, 1, 1, 3, 3, 3. Find the total number of possible guesses for all three prizes consistent with the hint.

Solution

Since we have 3 numbers, consider how many ways we can put this 3 number in a string of 7 digits by putting A,B,C together

For example: A=113, B=13, C=31

Then the string is

1131331

Since the strings have 7 digits and 3 three's. There are

_7C_3 of such string

In other to obtain all combination of A,B,C. We partition all the possible strings into 3 groups

Let look at the example.

We have to partition it into 3 groups with each group having at least 1 digit

We have to find solution where

x+y+z=7, 0<x,y,z<5

This gives us:

_6C_2 (balls and urns)

But we have counted the one with 5 digit numbers. That is (5,1,1),(1,1,5),(1,5,1)

Thus, each arrangement has (_6C_2)-3=12 ways per arrangement

Thus, there are (12)(35)ways=\boxed{420}

See also

2009 AIME I (ProblemsResources)
Preceded by
Problem 8
Followed by
Problem 10
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
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