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2009 AMC 10A Problems/Problem 1

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Problem

One can holds 12 ounces of soda. What is the minimum number of cans needed to provide a gallon (128 ounces) of soda?

\mathrm{(A)}\ 7\qquad\mathrm{(B)}\ 8\qquad\mathrm{(C)}\ 9\qquad\mathrm{(D)}\ 10\qquad\mathrm{(E)}\ 11

Solution

10 cans would hold 120 ounces, but 128>120, so 11 cans are required. Thus, the answer is \mathrm{(E)}.

2009 AMC 10A (ProblemsResources)
Preceded by
First Question
Followed by
Problem 2
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