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2009 AMC 10A Problems/Problem 18

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Problem

At Jefferson Summer Camp, 60\% of the children play soccer, 30\% of the children swim, and 40\% of the soccer players swim. To the nearest whole percent, what percent of the non-swimmers play soccer?

\mathrm{(A)}\ 30\%\qquad\mathrm{(B)}\ 40\%\qquad\mathrm{(C)}\ 49\%\qquad\mathrm{(D)}\ 51\%\qquad\mathrm{(E)}\ 70\%

Solution

Out of the soccer players, 40\% swim. As the soccer players are 60\% of the whole, the swimming soccer players are 0.4 \cdot 0.6 = 0.24 = 24\% of all children.

The non-swimming soccer players then form 60\% - 24\% = 36\% of all the children.

Out of all the children, 30\% swim. We know that 24\% of all the children swim and play soccer, hence 30\%-24\% = 6\% of all the children swim and don't play soccer.

Finally, we know that 70\% of all the children are non-swimmers. And as 36\% of all the children do not swim but play soccer, 70\% - 36\% = 34\% of all the children do not engage in any activity.

A quick summary of what we found out:

  • 24\%: swimming yes, soccer yes
  • 36\%: swimming no, soccer yes
  • 6\%: swimming yes, soccer no
  • 34\%: swimming no, soccer no

Now we can compute the answer. Out of all children, 70\% are non-swimmers, and again out of all children 36\% are non-swimmers that play soccer. Hence the part of non-swimmers that plays soccer is \frac{36}{70} \simeq \boxed{51\%}.

See Also

2009 AMC 10A (ProblemsResources)
Preceded by
Problem 17
Followed by
Problem 19
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