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2009 AMC 10B Problems/Problem 2

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Problem

Which of the following is equal to \dfrac{\frac{1}{3}-\frac{1}{4}}{\frac{1}{2}-\frac{1}{3}}?

\text{(A) } \frac 14\qquad\text{(B) } \frac 13\qquad\text{(C) } \frac 12\qquad\text{(D) } \frac 23\qquad\text{(E) } \frac 34

Solution

Multiplying the numerator and the denumerator by the same value does not change the value of the fraction. We can multiply both by 12, getting \dfrac{4-3}{6-4} = \boxed{\dfrac 12}.

Alternately, we can directly compute that the numerator is \dfrac 1{12}, the denumerator is \dfrac 16, and hence their ratio is \dfrac 12.

See Also

2009 AMC 10B (ProblemsResources)
Preceded by
Problem 1
Followed by
Problem 3
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