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2009 AMC 12A Problems/Problem 7

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Problem

The first three terms of an arithmetic sequence are 2x - 3, 5x - 11, and 3x + 1 respectively. The nth term of the sequence is 2009. What is n?

\textbf{(A)}\ 255 \qquad \textbf{(B)}\ 502 \qquad \textbf{(C)}\ 1004 \qquad \textbf{(D)}\ 1506 \qquad \textbf{(E)}\ 8037

Solution

As this is an arithmetic sequence, the difference must be constant: (5x-11) - (2x-3) = (3x+1) - (5x-11). This solves to x=4. The first three terms then are 5, 9, and 13. In general, the n-th term is 1+4n. Solving 1+4n=2009 we get n=\boxed{502}.


See Also

2009 AMC 12A (ProblemsResources)
Preceded by
Problem 6
Followed by
Problem 8
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
Looking for a challenging algebra text? Preparing for MATHCOUNTS or the AMC exams?
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