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Binomial Theorem

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The Binomial Theorem states that for real or complex , , and non-negative integer ,

(a+b)^n = \sum_{k=0}^{n}\binom{n}{k}a^{n-k}b^k

where \binom{n}{k} = \frac{n!}{k!(n-k)!} is a binomial coefficient. This result has a nice combinatorial proof: (a+b)^n=\underbrace{ (a+b)\cdot(a+b)\cdot(a+b)\cdot\cdots\cdot(a+b) }_{n}. Repeatedly using the distributive property, we see that for a term , we must choose of the terms to contribute an to the term, and then each of the other terms of the product must contribute a . Thus, the coefficient of is . Extending this to all possible values of from to , we see that (a+b)^n = \sum_{k=0}^{n}{\binom{n}{k}}\cdot a^k\cdot b^{n-k}.

Contents

Generalizations

The Binomial Theorem was generalized by Isaac Newton, who used an infinite series to allow for complex exponents: For any real or complex , , and ,

(a+b)^r = \sum_{k=0}^{\infty}\binom{r}{k}a^{r-k}b^k.

Proof

Consider the function for constants . It is easy to see that \frac{d^k}{db^k}f=r(r-1)\cdots(r-k+1)(a+b)^{r-k}. Then, we have \frac{d^k}{db^k}f(0)=r(r-1)\cdots(r-k+1)a^{r-k}. So, the Taylor series for centered at is

(a+b)^k=\sum_{k=0}^\infty \frac{r(r-1)\cdots(r-k+1)a^{r-k}b^k}{k!}=\sum_{k=0}^\infty \binom{r}{k}a^{r-k}b^k.

Usage

Many factorizations involve complicated polynomials with binomial coefficients. For example, if a contest problem involved the polynomial , one could factor it as such: x(x^4+4x^3+6x^2+4x+1)=x(x+1)^{4}. It is a good idea to be familiar with binomial expansions, including knowing the first few binomial coefficients.

See also

Looking for a challenging geometry text? Preparing for MATHCOUNTS or the AMC exams? Check out Art of Problem Solving's Introduction to Geometry by Richard Rusczyk.
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