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Dirichlet convolution

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For two functions f, g : \mathbb{N} \rightarrow \mathbb{C}, the Dirichlet convolution (or simply convolution, when the context is clear) of and is defined as

\sum_{d\mid n} f(d)g\left( \frac{n}{d} \right).

We usually only consider positive divisors of . We are often interested in convolutions of weak multiplicative functions; the set of weak multiplicative functions is closed under convolution. In general, convolution is commutative and associative; it also has an identity, the function defined to be 1 if , and 0 otherwise. Not all functions have inverses (e.g., the function \displaystyle f(n) : n \mapsto 0 has no inverse, as , for all functions g: \mathbb{N} \rightarrow \mathbb{C}), although all functions such that have inverses.

Closure of Weak Multiplicative Functions Under Convolution

Theorem. If f,g : \mathbb{N} \rightarrow \mathbb{C} are weak multiplicative functions, then so is .

Proof. Let be relatively prime. We wish to prove that \displaystyle (f*g)(mn) = (f*g)(m)\cdot (f*g)(n).

For , let be the set of divisors of . For relatively prime , we claim that the function is a bijection from to . Indeed, for any and , so p({\rm D}_m \times {\rm D}_n) \subseteq {\rm D}_{mn}. Furthermore, for each , there exist unique such that , , . Thus is bijective. As a result of our claim, we have the identity

\sum_{d_m \mid m, d_n \mid n}a(d_m)b(d_n) = \sum_{d_m \mid m} a(d_m) \cdot \sum_{d_n \mid n}b(d_n),

for any functions mapping subsets of into . In particular, we may let the domains of and be \displaystyle {\rm D}_m, {\rm D}_n, and define \displaystyle a(d_m) = f(d_m)g(m/d_m) and \displaystyle b(d_n) = f(d_n)g(n/d_n). We then have

\sum_{d_m \mid m}f(d_m)g(m/d_m) \cdot \sum_{d_n \mid n}f(d_n)g(n/d_n) = \sum_{d_m \mid m, d_n \mid n}f(d_m)g(m/d_m)f(d_n)g(n/d_n).

But since each divisor of is relatively prime to every divisor of , we have

\sum_{d_m \mid m, d_n \mid n}f(d_m)g(m/d_m)f(d_n)g(n/d_n) = \sum_{d_m \mid m, d_n \mid n}f(d_md_n)g\left(\frac{mn}{d_md_n}\right) = \sum_{d \mid mn}f(d)g(mn/d),

as desired.

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