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Geometric sequence

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A geometric sequence is a sequence of numbers in which each term is a fixed multiple of the previous term. For example: 1, 2, 4, 8, 16, 32, ... is a geometric sequence because each term is twice the previous term. In this case, 2 is called the common ratio of the sequence. More formally, a geometric sequence may be defined recursively by:

a_n = r\cdot a_{n-1}, n > 1

with a fixed first term a_1 and common ratio r. Using this definition, the nth term has the closed-form:

\displaystyle a_n = a_1\cdot r^{n-1}

Contents

Summing a Geometric Sequence

The sum of the first n terms of a geometric sequence is given by

S_n = a_1 + a_2 + \ldots + a_n = a_1\cdot\frac{r^n-1}{r-1}

where a_1 is the first term in the sequence, and r is the common ratio.

Infinite Geometric Sequences

An infinite geometric sequence is a geometric sequence with an infinite number of terms. If the common ratio is small, the terms will approach 0 and the sum of the terms will approach a fixed limit. In this case, "small" means |r|<1. We say that the sum of the terms of this sequence is a convergent sum.

For instance, the series 1 + \frac12 + \frac14 + \frac18 + \cdots, sums to 2. The general formula for the sum of such a sequence is:

S = \frac{a_1}{1-r}.


Where a_1 is the first term in the sequence, and r is the common ratio.

"Proof": Let the sequence be

S=a_1+a_1r+a_1r^2+a_1r^3+\cdots

Multiplying by r yields,

S \cdot r=a_1r+a_1r^2+a_1r^3+\cdots

We subtract these two equations to obtain:

S-Sr=a_1

There is only one term on the RHS because the rest of the terms cancel out after subtraction. Finally, we can factor and divide to get

\displaystyle S(1-r)=a_1

thus,

S=\frac{a_1}{1-r}

This method of multiplying the sequence and subtracting equations, called telescoping, is a frequently used method to evaluate infinite sequences. In fact, the same method can be used to calculate the sum of a finite geometric sequence (given above).

One common instance of summing infinite geometric sequences is the decimal expansion of most rational numbers. For instance, 0.33333\ldots = \frac 3{10} + \frac3{100} + \frac3{1000} + \frac3{10000} + \ldots has first term a_0 = \frac 3{10} and common ratio \frac1{10}, so the infinite sum has value S = \frac{\frac3{10}}{1-\frac1{10}} = \frac13, just as we would have expected.

Problems

Intermediate

See also

Looking for a challenging algebra text? Preparing for MATHCOUNTS or the AMC exams?
Check out Art of Problem Solving's Introduction to Algebra by Richard Rusczyk.
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