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Jensen's Inequality

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Jensen's Inequality is an inequality discovered by a mathematician of that name in 1906.

Contents

Inequality

Let be a convex function of one real variable. Let and let satisfy . Then


F(a_1x_1+\dots+a_n x_n)\le a_1F(x_1)+\dots+a_n F(x_n)


Proof

The proof of Jensen's inequality is very simple. Since the graph of every convex function lies above its tangent line at every point, we can compare the function with the linear function , whose graph is tangent to the graph of at the point . Then the left hand side of the inequality is the same for and , while the right hand side is smaller for . But the inequality for is an identity!

The simplest example of the use of Jensen's inequality is the quadratic mean - arithmetic mean inequality. Take (verify that and ) and . You'll get \left(\frac{x_1+\dots+x_n}{n}\right)^2\le \frac{x_1^2+\dots+ x_n^2}{n}. Similarly, arithmetic mean-geometric mean inequality can be obtained from Jensen's inequality by considering .

Problems

Introductory

Seeing as this is quite a complicated theorem, there are no introductory problems.

Intermediate

  • Prove that for any , we have \sin{A}+\sin{B}+\sin{C}\leq \frac{3\sqrt{3}}{2}.

Olympiad

  • Let be positive real numbers. Prove that

\frac{a}{\sqrt{a^{2}+8bc}}+\frac{b}{\sqrt{b^{2}+8ca}}+\frac{c}{\sqrt{c^{2}+8ab}}\ge 1 (Source)

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