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Power of a Point Theorem/Introductory Problem 3

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Problem

(ARML) In a circle, chords AB and CD intersect at R. If AR:BR = 1:4 and CR:DR = 4:9, find the ratio AB:CD.

Image:popprob3.PNG

Solution

Letting AR = x makes BR = 4x. Similarly, letting CR = 4y makes DR = 9y. Thus AB = AR + BR = x + 4x = 5x and CD = CR + DR = 4y + 9y = 13y. We therefore seek \frac{AB}{CD} = \frac{5x}{13y}.

From the Power of a Point Theorem, we have that

x\cdot 4x = 4y\cdot 9y\Rightarrow \left(\frac xy\right)^2 = 9,

which gives \frac xy = \pm 3, so we take \frac xy = 3.

Finally,

\frac{5x}{13y}=\frac 5{13}\cdot \frac xy = \frac 5{13}\cdot 3 = \frac{15}{13}.

Back to the Power of a Point Theorem.

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