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Power of a Point Theorem/Introductory Problem 4

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Problem

(ARML) Chords AB and CD of a given circle are perpendicular to each other and intersect at a right angle. Given that BE = 16, DE = 4, and AD = 5, find CE.

Solution

ADE is a right triangle with hypotenuse 5 and leg 4. Thus, by the Pythagorean Theorem, AE = 3 (or by just knowing your Pythagorean Triples). Applying the Power of a Point Theorem gives AE\cdot BE = CE\cdot DE, or 3\cdot 16 = x\cdot 4. Solving gives x = 12.

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