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University of South Carolina High School Math Contest/1993 Exam/Problem 13

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Problem

Suppose that x and y are numbers such that \sin(x+y) = 0.3 and \sin(x-y) = 0.5. Then \sin (x)\cdot \cos (y) =

\mathrm{(A) \ }0.1 \qquad \mathrm{(B) \ }0.3 \qquad \mathrm{(C) \ }0.4 \qquad \mathrm{(D) \ }0.5 \qquad \mathrm{(E) \ }0.6

Solution

Expanding \sin{(x+y)} and \sin{(x-y)}, we have: (1) \sin{x}\cos{y}+\sin{y}\cos{x}=.3 (2) \sin{x}\cos{y}-\sin{y}\cos{x}=.5

(1)+(2) yields 2\sin{x}\cos{y}=.8 and our answer is .4.


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