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University of South Carolina High School Math Contest/1993 Exam/Problem 25

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Problem

What is the center of the circle passing through the point (6,0) and tangent to the circle x^2 + y^2 = 4 at (0,2)? (Two circles are tangent at a point P if they intersect at P and at no other point.)

\mathrm{(A) \ }(0,-6) \qquad \mathrm{(B) \ } (1,-9) \qquad \mathrm{(C) \ } (-1,-9) \qquad \mathrm{(D) \ } (0,-9) \qquad \math...

Solution

Let the circle we are looking for be (x-h)^{2}+(y-k)^{2}=r^{2} where (h,k) is obviously the center. Plugging in points (6,0) and (0,2) gives us that 3k-h=8. Seeing our answer choices, none of the points work, thus our answer is E.


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