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1990 USAMO Problems/Problem 1

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Problem

A certain state issues license plates consisting of six digits (from 0 through 9). The state requires that any two plates differ in at least two places. (Thus the plates \boxed{027592} and \boxed{020592} cannot both be used.) Determine, with proof, the maximum number of distinct license plates that the state can use.

Solutions

Consider license plates of n digits, for some fixed n, issued with the same criteria.

We first note that by the pigeonhole principle, we may have at most 10^{n-1} distinct plates. Indeed, if we have more, then there must be two plates which agree on the first n-1 plates; these plates thus differ only on one digit, the last one.

We now show that it is possible to issue 10^{n-1} distinct license plates which satisfy the problem's criteria. Indeed, we issue plates with all 10^{n-1} possible combinations for the first n-1 digit, and for each plate, we let the last digit be the sum of the preceding digits taken mod 10. This way, if two plates agree on the first n-1 digits, they agree on the last digit and are thus the same plate, and if two plates differ in only one of the first n-1 digits, they must differ as well in the last digit.

It then follows that 10^{n-1} is the greatest number of license plates the state can issue. For n=6, as in the problem, this number is 10^5. \blacksquare


Alternate solutions are always welcome. If you have a different, elegant solution to this problem, please add it to this page.

See also

1990 USAMO (Problems • Resources: AoPS | ML)
Preceded by
First question
1 2 3 4 5 6 Followed by
Problem 2
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