1998 APMO Problems/Problem 4
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Problem
(Răzvan Gelca)
Let
be a triangle and
the foot of the altitude from
. Let
and
be on a line through
such that
is perpendicular to
,
is perpendicular to
, and
and
are different from
. Let
and
be the midpoints of the line segments
and
, respectively. Prove that
is perpendicular to
.
Solution
Since
and
are both right angles, points
are concyclic. It follows that
Similarly, the quadrilateral
is cyclic, so
Thus
and
are similar triangles, so
and
are similar figures. It follows that
so points
are concyclic. Since
is a right angle, it then follows that
is a right angle, as desired.
Alternate solutions are always welcome. If you have a different, elegant solution to this problem, please add it to this page.







