2000 AIME II Problems/Problem 5
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Problem
Given eight distinguishable rings, let 
be the number of possible five-ring arrangements on the four fingers (not the thumb) of one hand. The order of rings on each finger is significant, but it is not required that each finger have a ring. Find the leftmost three nonzero digits of .
Solution
There are 
ways to choose the rings, and there are 
distinct arrangements to order the rings [we order them so that the first ring is the bottom-most on the first finger, and so forth]. The number of ways to distribute the rings among the fingers is equivalent the number of ways we can drop five balls into 4 urns, or similarly dropping five balls into four compartments split by three dividers. The number of ways to arrange those dividers and balls is just 
.
Multiplying gives the answer: 
, and the three leftmost digits are 
.
See also
| 2000 AIME II (Problems • Resources) | ||
| Preceded by Problem 4 | Followed by Problem 6 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
