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2004 AMC 12A Problems/Problem 12

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Problem

Let A = (0,9) and B = (0,12). Points A' and B' are on the line y = x, and \overline{AA'} and \overline{BB'} intersect at C = (2,8). What is the length of \overline{A'B'}?

\text {(A)} 2 \qquad \text {(B)} 2\sqrt2 \qquad \text {(C)} 3 \qquad \text {(D)} 2 + \sqrt 2\qquad \text {(E)}3\sqrt 2

Solution

Image:2004_AMC_12A-12.png

The equation of \overline{AA'} can be found using points A, C to be y - 9 = \left(\frac{9-8}{0-2}\right)(x - 0) \Longrightarrow y = -\frac{1}{2}x + 9. Similarily, \overline{BB'} has the equation y - 12 = \left(\frac{12-8}{0-2}\right)(x-0) \Longrightarrow y = -2x + 12. These two equations intersect the line y=x at (6,6) and (4,4). Using the distance formula or 45-45-90 right triangles, the answer is 2\sqrt{2}\ \mathrm{(B)}.

See also

2004 AMC 12A (ProblemsResources)
Preceded by
Problem 11
Followed by
Problem 13
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