AoPSWiki
Try our innovative online adaptive learning system, Alcumus.
Over 1100 problems and 60+ video lessons. FREE!

Lagrange's Theorem

From AoPSWiki

Lagrange's theorem is a result on the indices of cosets of a group.

Theorem. Let G be a group, H a subgroup of G, and K a subgroup of H. Then (G:K) = (G:H)(H:K) .

Proof. For any a\in G, note that aK \subseteq aH; thus each left coset mod K is a subset of a left coset mod H; since each element of G is in some left coset mod K, it follows that the left cosets mod H are unions of left cosets mod K. Furthermore, the mapping x\mapsto ba^{-1}x induces a bijection from the left cosets mod K contained in an arbitrary H-coset aH to those contained in an arbitrary H-coset bH. Thus each H-coset is a union of K-cosets, and the cardinality of the set of K-cosets contained in an H-coset is independent of the choice of the H-coset. The theorem then follows. \blacksquare

By letting K be the trivial subgroup, we have |G| = (G:H) |H|. In particular, if G is a finite group of order G and H is a subgroup of G of order h, g = (G:H) h, so the index and order of H are divisors of g.

See also

Stay informed about new Art of Problem Solving developments.
Click here to join our mailing lists.
© Copyright 2008 AoPS Incorporated. All Rights Reserved. • FoundationPrivacyContact Us