Create the page "Sophie Germain Identity." on this wiki! See also the search results found.

Page title matches

• Sophie Germain Identity
  The '''Sophie Germain Identity''' states that: ...history.st-andrews.ac.uk/Biographies/Germain/ MacTutor biography of Sophie Germain]
  2 KB (222 words) - 15:04, 30 December 2023

Page text matches

• Factoring
  * [[Sophie Germain Identity]]
  3 KB (532 words) - 22:00, 13 January 2024
• Algebra/Intermediate
  ** [[Sophie Germain Identity]]
  2 KB (198 words) - 17:47, 3 November 2021
• 1987 AIME Problems/Problem 14
  == Solution 1 (Sophie Germain Identity) == ...> Each of the terms is in the form of <math>x^4 + 324.</math> Using Sophie Germain, we get that
  7 KB (965 words) - 10:42, 12 April 2024
• Sophie Germain Identity
  The '''Sophie Germain Identity''' states that: ...history.st-andrews.ac.uk/Biographies/Germain/ MacTutor biography of Sophie Germain]
  2 KB (222 words) - 15:04, 30 December 2023
• Mock AIME 5 2005-2006 Problems/Problem 5
  <math>25^2+72^2=5^4+4\cdot 6^4</math>, and we can use the [[Sophie Germain Identity]] on that to get
  484 bytes (60 words) - 16:23, 2 March 2008
• Mock AIME 1 2007-2008 Problems/Problem 12
  (If you recall the reverse of [[Sophie Germain Identity]] with <math>a=a,\, b = 2^{(a-1)/2}</math>, then you could have di
  2 KB (237 words) - 12:08, 10 March 2012
• 1954 AHSME Problems/Problem 32
  So, using the [[Sophie Germain Identity]], we can factor the expression as:
  733 bytes (112 words) - 01:52, 28 February 2020
• 2020 AMC 10B Problems/Problem 22
  ...lynomial division, but the numerator looks awfully similar to the [[Sophie Germain Identity]], which states that <cmath>a^4+4b^4=(a^2+2b^2+2ab)(a^2+2b^2-2ab) ...math>4x^{4} + 1 = (2x^{2} + 2x + 1)(2x^{2} - 2x + 1)</cmath> by the Sophie Germain identity so to find <cmath>4x^{4} + 202,</cmath> we find that <cmath>4x^{4}
  4 KB (516 words) - 09:52, 9 March 2024