Difference between revisions of "1951 AHSME Problems/Problem 4"

m
Line 7: Line 7:
 
The walls are <math>13*5=65</math> and <math>10*5=50</math> in area, and the ceiling has an area of <math>10*13=130</math>.
 
The walls are <math>13*5=65</math> and <math>10*5=50</math> in area, and the ceiling has an area of <math>10*13=130</math>.
  
<math>((65+50)2)2+130=590 \Rightarrow \boxed{\mathrm{(D) \ }}</math>
+
<math>((65+50)2)2+130=590 \Rightarrow \boxed{\mathrm{(D)}}</math>
  
 
==See also==
 
==See also==

Revision as of 10:01, 5 February 2008

Problem

A barn with a roof is rectangular in shape, $10$ yd. wide, $13$ yd. long and $5$ yd. high. It is to be painted inside and outside, and on the ceiling, but not on the roof or floor. The total number of sq. yd. to be painted is:

$\mathrm{(A) \ } 360 \qquad \mathrm{(B) \ } 460 \qquad \mathrm{(C) \ } 490 \qquad \mathrm{(D) \ } 590 \qquad \mathrm{(E) \ } 720$

Solution

The walls are $13*5=65$ and $10*5=50$ in area, and the ceiling has an area of $10*13=130$.

$((65+50)2)2+130=590 \Rightarrow \boxed{\mathrm{(D)}}$

See also