Difference between revisions of "AoPS Wiki talk:Problem of the Day/July 4, 2011"
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==Solution== | ==Solution== | ||
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+ | <math>3^x-3 \equiv 0 \mod 16 \Rightarrow 3^x \equiv 3 \mod 16</math>. | ||
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+ | So <math>3^x</math> cycles through 3,9,11,1 mod 16, <math>x = 1</math> doesn't work so try <math>x = 5</math> which works and we're done. |
Latest revision as of 10:50, 4 July 2011
Problem
AoPSWiki:Problem of the Day/July 4, 2011
Solution
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So cycles through 3,9,11,1 mod 16, doesn't work so try which works and we're done.