Difference between revisions of "1959 AHSME Problems/Problem 22"
(Created page with "Let x be the length of the shorter base. 3 = (97 - x)/2 6 = 97 - x x = 91 Thus, 91.") |
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Let x be the length of the shorter base. | Let x be the length of the shorter base. | ||
3 = (97 - x)/2 | 3 = (97 - x)/2 | ||
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6 = 97 - x | 6 = 97 - x | ||
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x = 91 | x = 91 | ||
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Thus, 91. | Thus, 91. | ||
Revision as of 10:29, 22 August 2018
Let x be the length of the shorter base. 3 = (97 - x)/2
6 = 97 - x
x = 91
Thus, 91.
