Difference between revisions of "AoPS Wiki talk:Problem of the Day/June 17, 2011"
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==Solution== | ==Solution== | ||
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| + | <math> \frac{1^{3}+2^{3}+3^{3}+\cdots+x^{3}}{1+2+3+\cdots+x}=\frac{(1+2+3+\cdots+x)^2}{1+2+3+\cdots+x}=1+2+3+\cdots+x</math> | ||
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| + | <math>1+2+3+\cdots+x=\frac{x\cdot(x+1)}{2}</math> Subbing in the value of <math>x</math> we get,<math>\frac{9001\cdot9002}{2}=\boxed{40513501}</math> | ||
Subbing in the value of 
we get,
