Difference between revisions of "Specimen Cyprus Seniors Provincial/2nd grade/Problem 1"
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a) the distance of <math>\Gamma</math> from <math>(\epsilon)</math> is equal to the sum of the distances <math>B, \Delta</math> from <math>(\epsilon)</math>. | a) the distance of <math>\Gamma</math> from <math>(\epsilon)</math> is equal to the sum of the distances <math>B, \Delta</math> from <math>(\epsilon)</math>. | ||
| − | b)Area(<math>B\Gamma\Delta</math>)=Area(<math>B'\Gamma '\Delta '</math>) | + | b)Area(<math>B\Gamma\Delta</math>)=Area(<math>B'\Gamma '\Delta '</math>). |
== Solution == | == Solution == | ||
Revision as of 07:06, 12 November 2006
Problem
Let 
be a parallelogram. Let 
be a straight line passing through 
without cutting . If 
are the projections of 
on respectively, show that
a) the distance of 
from is equal to the sum of the distances 
from .
b)Area(
)=Area(
).
