1976 AHSME Problems/Problem 9
Revision as of 12:59, 17 February 2021 by Justinlee2017 (talk | contribs) (Created page with "==Solution== Let <math>[ABC]</math> denote the area of <math>ABC</math> Since <math>F</math> is the midpoint of <math>|BC|</math>, we have <math>[ABF] = [ACF] = \frac{96}{2}...")
Solution
Let denote the area of
Since
is the midpoint of
, we have
is the midpoint of
, so
Now we just need to find
, since
In
,
is the midpoint of
, so
Thus,
~JustinLee2017