Difference between revisions of "2024 AIME II Problems/Problem 15"

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AIME hasn't been released yet. This is a placeholder.
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==Problem==
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Find the number of rectangles that can be formed from a regular dodecagon such that each side of the rectangle lies on either a side or a diagonal of the dodecagon. The diagram below shows three of those rectangles.
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<asy>
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unitsize(60);
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real r = pi/6;
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pair A1 = (cos(r),sin(r));
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pair A2 = (cos(2r),sin(2r));
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pair A3 = (cos(3r),sin(3r));
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pair A4 = (cos(4r),sin(4r));
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pair A5 = (cos(5r),sin(5r));
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pair A6 = (cos(6r),sin(6r));
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pair A7 = (cos(7r),sin(7r));
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pair A8 = (cos(8r),sin(8r));
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pair A9 = (cos(9r),sin(9r));
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pair A10 = (cos(10r),sin(10r));
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pair A11 = (cos(11r),sin(11r));
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pair A12 = (cos(12r),sin(12r));
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draw(A1--A2--A3--A4--A5--A6--A7--A8--A9--A10--A11--A12--cycle);
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filldraw(A3--A2--A9--A8--cycle, mediumgray);
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draw(A5--A12);
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dot(0.365*A4);
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dot(0.365*A1);
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dot(A1);
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dot(A2);
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dot(A3);
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dot(A4);
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dot(A5);
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dot(A6);
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dot(A7);
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dot(A8);
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dot(A9);
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dot(A10);
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dot(A11);
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dot(A12);
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</asy>
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==See also==
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{{AIME box|year=2024|n=II|num-b=14|after=Last Problem}}
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[[Category:Intermediate Combinatorics Problems]]
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{{MAA Notice}}

Revision as of 18:01, 8 February 2024

Problem

Find the number of rectangles that can be formed from a regular dodecagon such that each side of the rectangle lies on either a side or a diagonal of the dodecagon. The diagram below shows three of those rectangles.

[asy] unitsize(60); real r = pi/6; pair A1 = (cos(r),sin(r)); pair A2 = (cos(2r),sin(2r)); pair A3 = (cos(3r),sin(3r)); pair A4 = (cos(4r),sin(4r)); pair A5 = (cos(5r),sin(5r)); pair A6 = (cos(6r),sin(6r)); pair A7 = (cos(7r),sin(7r)); pair A8 = (cos(8r),sin(8r)); pair A9 = (cos(9r),sin(9r)); pair A10 = (cos(10r),sin(10r)); pair A11 = (cos(11r),sin(11r)); pair A12 = (cos(12r),sin(12r)); draw(A1--A2--A3--A4--A5--A6--A7--A8--A9--A10--A11--A12--cycle); filldraw(A3--A2--A9--A8--cycle, mediumgray); draw(A5--A12); dot(0.365*A4); dot(0.365*A1); dot(A1); dot(A2); dot(A3); dot(A4); dot(A5); dot(A6); dot(A7); dot(A8); dot(A9); dot(A10); dot(A11); dot(A12); [/asy]

See also

2024 AIME II (ProblemsAnswer KeyResources)
Preceded by
Problem 14
Followed by
Last Problem
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
All AIME Problems and Solutions

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