Difference between revisions of "2018 UNM-PNM Statewide High School Mathematics Contest II Problems/Problem 4"
(→Solution) |
(→Solution) |
||
Line 9: | Line 9: | ||
Let any one side be x and other side be y. | Let any one side be x and other side be y. | ||
− | Then one diagonal is | + | Then one diagonal is \sqrt{<math>y^{2}</math> <math>-</math> <math>x^{2}</math>} |
let [(y)^2-(x)^2]^(1/2) be z. | let [(y)^2-(x)^2]^(1/2) be z. |
Revision as of 06:33, 9 August 2019
Problem
Suppose ABCD is a parallelogram with area square units and is a right angle. If the lengths of all the sides of ABCD are integers, what is the perimeter of ABCD?
Solution
(Involves Hit and Trial) Let any one side be x and other side be y.
Then one diagonal is \sqrt{ }
let [(y)^2-(x)^2]^(1/2) be z.
So x*z=39*95^(1/2)
Here x = 13 satisfies with y = 32 { By Hit And Trial Method }
so Perimeter is 2(13+32)=90
See also
2018 UNM-PNM Contest II (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 | ||
All UNM-PNM Problems and Solutions |