Elegant, not Elephant : Part II
by Ankoganit, Aug 2, 2016, 5:15 AM
This post is a sequel to my previous blog post: Elegant, not Elephant. As before, I aim to collect and present some more instances of mathematical problems, which are seemingly unassailable but are deceptively simple. The topics vary widely : combinatorics, algebra, geometry -- but a common theme of innate elegance binds them together.
OK, I guess that's enough of a prologue; let's start this off with a rather famous one:
One hundred ants are dropped on a meter stick. Each ant is traveling either to the left or the right with constant speed
meter per minute. When two ants meet, they bounce off each other and reverse direction. When an ant reaches an end of the stick, it falls off. Over all possible initial configurations, what is the longest amount of time that you would need to wait to guarantee that the stick has no more ants?
Solution
A rectangle is called special if at least one of its sides has integer length. Suppose a rectangle is tiled by rectangles each of which is special. Prove that the big rectangle itself is special.
Solution
is the median of the triangle
, and
and
are incenters of
and
respectively. Given that
is cyclic, prove that
is
isosceles.
Solution
Suppose we can place
equal disk-shaped coins on a rectangular table such that no two coins overlap and it's impossible to place another coin on the table without causing overlap. Prove that allowing overlap, we can cover the table entirely using no more than
coins. Note that a coin can stay on the table iff its center lies on the table.
Solution
roads on a plane, each a straight line, are in general position so that no two are parallel and no three pass through the same point. Along each road walks a traveler at a constant speed. Their speeds, however, may not be the same. It's known that traveler
met with Travelers
, and each of the other travellers met both Traveller
and
. Show that any two travellers met each other.
Solution
Appendix: Here's another of my favourite ones; I didn't include it above since this proof is disregarded by many mathematicians.
Hex Theorem : The game of Hex cannot end in a draw.
Proof
Sources:
6. Su, Francis E., et al. "Ants on a Stick." Math Fun Facts. http://www.math.hmc.edu/funfacts.
7. Stan Wagon, Fourteen Proofs of a Result About Tiling a Rectangle.
8. PDC, India, 2016
9. An AoPS topic here.
10. Four Traveller's Problem at Cut-The-Knot , http://www.cut-the-knot.org/gproblems.shtml
Appendix: http://www.cut-the-knot.org/Curriculum/Games/HexTheory.shtml
OK, I guess that's enough of a prologue; let's start this off with a rather famous one:


Solution
Give each ant a flag, and let them exchange flags when two ants meet. Note that each flag travels with a constant speed of
meter/second without changing direction. Since the stick is free of ants if and only if it's free of flags, the longest one needs to wait is
s. 




Solution
Here are two proofs of the wonderful result. The paper mentioned below in the sources contains
different and equally elegant proofs of this, using tools ranging from graph theory and coloring to polynomials and complex double integrals. The "!" sign is left to the reader.
Proof 1: Introduce Cartesian coordinates such that the sides of the rectangle are parallel to the axes and the bottom left corner is at the origin. Now divide the plane into
rectangles (with edges parallel to axes) and colour them black and white in a chessboard fashion. Note that a rectangle is special if and only if it contains equal amounts of black and white area. Since the constituent rectangles satisfy this, the whole rectangle must also contain same amount of black and white area, and hence must be special. 
Proof 2. Introduce coordinates as before, and let
be the set of lattice points which are corners of some tile, and
be the set of tiles. Consider a bipartite graph on
with
and
joined if and only if
is a corner of
. Notice that all the tiles have degree
or
, i.e., always even. Now
has odd degree, so there must be some other point with odd degree (sum of degrees is even), which can happen only for corner points of the big rectangle (check it yourself). So some other corner must have integer coordinates, implying the result. 

Proof 1: Introduce Cartesian coordinates such that the sides of the rectangle are parallel to the axes and the bottom left corner is at the origin. Now divide the plane into


Proof 2. Introduce coordinates as before, and let





















Solution
OK, this one deserves some story. It so happened that we were told this problem at the Pre-Departure camp for IMO,and we tried for some hours, to get a variety of different solutions : one using a Russian problem as a lemma, one using orthology, one by inversion and so on. After some time, I came up with the following argument:
Let
be the incenter of
, and note that the facts that
and
passes through the circumcenter of
imply that
is the altitude of
. Now supposing
, one finds that
has a greater inradius than
, and hence
"tilts" on the right side, and so it can't be perpendicular to
, which is tilting to the left side. 
It is pretty easy to embed the above idea into a formal proof by incorporating some angle chase. Soon after, one of our trainers came up with the following:
Say
. Since
is antiparallel to
, it must tilt on the left side (i.e., has a positive slope if
is horizontal), and since
has a greater inradius, it has to tilt the opposite way. Contradiction. 
Let













It is pretty easy to embed the above idea into a formal proof by incorporating some angle chase. Soon after, one of our trainers came up with the following:
Say









Solution
Dilate each coin about its center with ratio
. Note that these mega-coins now cover the whole table (otherwise it would be possible to place another coin in the initial position without overlapping). Now Dilate the whole configuration about one of the corner of the table and with ratio
. Now
normal coins completely cover one quadrant of the table. Replicate this
times to cover the
other quadrants, and we will be done. 












Solution
Embed the plane into the
-d space, as the
-plane, and for each traveller, draw a graph of his motion with
axis as the time axis. Note that constant speed means each of these graphs are a straight line, and two travellers met if and only if their graphs intersect. Let
be the line corresponding to traveller
. Since
and
meet, they describe a plane
, and since each
meets
and
, it lies on
as well. Now that all lines are co-planar (and non-parallel), we conclude that any two of them must intersect. 













Appendix: Here's another of my favourite ones; I didn't include it above since this proof is disregarded by many mathematicians.
Hex Theorem : The game of Hex cannot end in a draw.
Proof
Quote:
Imagine the playing board for the game of Hex to be made out of paper. Whenever red moves, he colors the hexagon of his choice red. Whenever blue moves, he cuts out the hexagon of his choice. Repeat this until no one can move any more.
Pick up the playing board in your hands, holding the two 'red' edges. Pull your hands apart. Either the paper stops you, in which case there must be a path of red squares and so red wins; or nothing stops you, in which case there is a 'path' of cut out squares between the top and the bottom of the board, and so blue wins.
Clearly, one of the two must occur; and so someone must win.
Pick up the playing board in your hands, holding the two 'red' edges. Pull your hands apart. Either the paper stops you, in which case there must be a path of red squares and so red wins; or nothing stops you, in which case there is a 'path' of cut out squares between the top and the bottom of the board, and so blue wins.
Clearly, one of the two must occur; and so someone must win.
Sources:
6. Su, Francis E., et al. "Ants on a Stick." Math Fun Facts. http://www.math.hmc.edu/funfacts.
7. Stan Wagon, Fourteen Proofs of a Result About Tiling a Rectangle.
8. PDC, India, 2016
9. An AoPS topic here.
10. Four Traveller's Problem at Cut-The-Knot , http://www.cut-the-knot.org/gproblems.shtml
Appendix: http://www.cut-the-knot.org/Curriculum/Games/HexTheory.shtml
This post has been edited 1 time. Last edited by Ankoganit, Aug 2, 2016, 5:18 AM