2011 UNCO Math Contest II Problems/Problem 6

Problem

What is the remainder when $1! + 2! + 3! + \cdots + 2011!$ is divided by $18$?

Solution

Since all the terms past $5!$ are divisible by $18$, it is only necessary to look at the remainder resulted from the first 5 terms. $1!+2!+3!+4!+5!=153\equiv 9\pmod{18}$

See Also

2011 UNCO Math Contest II (ProblemsAnswer KeyResources)
Preceded by
Problem 5
Followed by
Problem 7
1 2 3 4 5 6 7 8 9 10
All UNCO Math Contest Problems and Solutions